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How to Fix - UnboundLocalError: Local variable Referenced Before Assignment in Python

Developers often encounter the  UnboundLocalError Local Variable Referenced Before Assignment error in Python. In this article, we will see what is local variable referenced before assignment error in Python and how to fix it by using different approaches.

What is UnboundLocalError: Local variable Referenced Before Assignment?

This error occurs when a local variable is referenced before it has been assigned a value within a function or method. This error typically surfaces when utilizing try-except blocks to handle exceptions, creating a puzzle for developers trying to comprehend its origins and find a solution.

Below, are the reasons by which UnboundLocalError: Local variable Referenced Before Assignment error occurs in  Python :

Nested Function Variable Access

Global variable modification.

In this code, the outer_function defines a variable ‘x’ and a nested inner_function attempts to access it, but encounters an UnboundLocalError due to a local ‘x’ being defined later in the inner_function.

In this code, the function example_function tries to increment the global variable ‘x’, but encounters an UnboundLocalError since it’s treated as a local variable due to the assignment operation within the function.

Solution for Local variable Referenced Before Assignment in Python

Below, are the approaches to solve “Local variable Referenced Before Assignment”.

In this code, example_function successfully modifies the global variable ‘x’ by declaring it as global within the function, incrementing its value by 1, and then printing the updated value.

In this code, the outer_function defines a local variable ‘x’, and the inner_function accesses and modifies it as a nonlocal variable, allowing changes to the outer function’s scope from within the inner function.

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【Python】成功解决python报错:UnboundLocalError: local variable ‘xxx‘ referenced before assignment

unboundlocalerror local variable 'connection' referenced before assignment

成功解决python报错:UnboundLocalError: local variable ‘xxx’ referenced before assignment。在Python中, UnboundLocalError 是一种特定的 NameError ,它会在尝试引用一个还未被赋值的局部变量时发生。Python解释器需要知道变量的类型和作用域,因此,在局部作用域内引用一个未被赋值的变量时,就会抛出这个错误。

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【Python】解决Python报错:

1. 什么是unboundlocalerror?, 2. 常见的场景和原因, 方法一:全局变量, 方法二:函数参数, 方法三:局部变量初始化, 方法四:结合条件语句.

在这里插入图片描述

在Python编程中, UnboundLocalError: local variable 'xxx' referenced before assignment 是一个常见的错误,尤其是在写函数时可能会遇到。这篇技术博客将详细介绍 UnboundLocalError ,为什么会发生,以及如何解决这个错误。

在Python中, UnboundLocalError 是一种特定的 NameError ,它会在尝试引用一个还未被赋值的局部变量时发生。Python解释器需要知道变量的类型和作用域,因此,在局部作用域内引用一个未被赋值的变量时,就会抛出这个错误。

这是一个简单的代码示例来说明这个错误:

运行以上代码会抛出以下错误:

在这个例子中,Python解释器看到 print(x) 时,寻找局部作用域中的变量 x ,但这个变量在局部作用域内尚未被赋值(虽然在后面有赋值,解释器是从上到下执行代码的)。

理解错误的原因后,可以通过以下几种方式来解决 UnboundLocalError :

如果变量希望在函数内和函数外都使用,可以将其声明为全局变量:

通过在函数内使用 global 关键字,将 x 声明为全局变量,这样即使在函数内也能访问全局变量 x 。

通过将变量作为参数传递给函数,使得函数内可以访问并使用这个变量:

在这种情况下, x 是函数 my_function 的一个参数,无需在函数内部声明。

在使用变量之前,先初始化该局部变量:

确保在函数内部引用变量之前,该变量已经被赋值。

在复杂的逻辑中,特别是在涉及条件语句时,可以先在函数开始部分初始化变量,确保无论哪条路径都可以正确访问该变量:

在这个例子中,我们确保了变量 x 在函数内部任何地方都能被适当地引用。

  • 命名冲突 :在全局变量和局部变量重名情况下,优先使用局部变量。如果不小心混用,容易引发错误。
  • 提前规划变量作用域 :代码设计时,可以提前规划好变量应该属于哪个作用域,以减少变量冲突和未定义变量的情况。

UnboundLocalError: local variable 'xxx' referenced before assignment 错误是一个常见的初学者错误,但只要理解了Python的变量作用域规则和执行顺序,就可以轻松避开。通过合适的解决方法,如使用全局变量、函数参数、局部变量初始化或结合条件语句,可以高效且清晰地管理变量的使用。

希望这篇文章能帮助你理解和解决这个错误。如果有任何问题或其他建议,欢迎在评论中与我们讨论。Happy coding!

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unboundlocalerror local variable 'connection' referenced before assignment

[SOLVED] Local Variable Referenced Before Assignment

local variable referenced before assignment

Python treats variables referenced only inside a function as global variables. Any variable assigned to a function’s body is assumed to be a local variable unless explicitly declared as global.

Why Does This Error Occur?

Unboundlocalerror: local variable referenced before assignment occurs when a variable is used before its created. Python does not have the concept of variable declarations. Hence it searches for the variable whenever used. When not found, it throws the error.

Before we hop into the solutions, let’s have a look at what is the global and local variables.

Local Variable Declarations vs. Global Variable Declarations

Local VariablesGlobal Variables
A variable is declared primarily within a Python function.Global variables are in the global scope, outside a function.
A local variable is created when the function is called and destroyed when the execution is finished.A Variable is created upon execution and exists in memory till the program stops.
Local Variables can only be accessed within their own function.All functions of the program can access global variables.
Local variables are immune to changes in the global scope. Thereby being more secure.Global Variables are less safer from manipulation as they are accessible in the global scope.

[Fixed] typeerror can’t compare datetime.datetime to datetime.date

Local Variable Referenced Before Assignment Error with Explanation

Try these examples yourself using our Online Compiler.

Let’s look at the following function:

Local Variable Referenced Before Assignment Error

Explanation

The variable myVar has been assigned a value twice. Once before the declaration of myFunction and within myFunction itself.

Using Global Variables

Passing the variable as global allows the function to recognize the variable outside the function.

Create Functions that Take in Parameters

Instead of initializing myVar as a global or local variable, it can be passed to the function as a parameter. This removes the need to create a variable in memory.

UnboundLocalError: local variable ‘DISTRO_NAME’

This error may occur when trying to launch the Anaconda Navigator in Linux Systems.

Upon launching Anaconda Navigator, the opening screen freezes and doesn’t proceed to load.

Try and update your Anaconda Navigator with the following command.

If solution one doesn’t work, you have to edit a file located at

After finding and opening the Python file, make the following changes:

In the function on line 159, simply add the line:

DISTRO_NAME = None

Save the file and re-launch Anaconda Navigator.

DJANGO – Local Variable Referenced Before Assignment [Form]

The program takes information from a form filled out by a user. Accordingly, an email is sent using the information.

Upon running you get the following error:

We have created a class myForm that creates instances of Django forms. It extracts the user’s name, email, and message to be sent.

A function GetContact is created to use the information from the Django form and produce an email. It takes one request parameter. Prior to sending the email, the function verifies the validity of the form. Upon True , .get() function is passed to fetch the name, email, and message. Finally, the email sent via the send_mail function

Why does the error occur?

We are initializing form under the if request.method == “POST” condition statement. Using the GET request, our variable form doesn’t get defined.

Local variable Referenced before assignment but it is global

This is a common error that happens when we don’t provide a value to a variable and reference it. This can happen with local variables. Global variables can’t be assigned.

This error message is raised when a variable is referenced before it has been assigned a value within the local scope of a function, even though it is a global variable.

Here’s an example to help illustrate the problem:

In this example, x is a global variable that is defined outside of the function my_func(). However, when we try to print the value of x inside the function, we get a UnboundLocalError with the message “local variable ‘x’ referenced before assignment”.

This is because the += operator implicitly creates a local variable within the function’s scope, which shadows the global variable of the same name. Since we’re trying to access the value of x before it’s been assigned a value within the local scope, the interpreter raises an error.

To fix this, you can use the global keyword to explicitly refer to the global variable within the function’s scope:

However, in the above example, the global keyword tells Python that we want to modify the value of the global variable x, rather than creating a new local variable. This allows us to access and modify the global variable within the function’s scope, without causing any errors.

Local variable ‘version’ referenced before assignment ubuntu-drivers

This error occurs with Ubuntu version drivers. To solve this error, you can re-specify the version information and give a split as 2 –

Here, p_name means package name.

With the help of the threading module, you can avoid using global variables in multi-threading. Make sure you lock and release your threads correctly to avoid the race condition.

When a variable that is created locally is called before assigning, it results in Unbound Local Error in Python. The interpreter can’t track the variable.

Therefore, we have examined the local variable referenced before the assignment Exception in Python. The differences between a local and global variable declaration have been explained, and multiple solutions regarding the issue have been provided.

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The Research Scientist Pod

Python UnboundLocalError: local variable referenced before assignment

by Suf | Programming , Python , Tips

If you try to reference a local variable before assigning a value to it within the body of a function, you will encounter the UnboundLocalError: local variable referenced before assignment.

The preferable way to solve this error is to pass parameters to your function, for example:

Alternatively, you can declare the variable as global to access it while inside a function. For example,

This tutorial will go through the error in detail and how to solve it with code examples .

Table of contents

What is scope in python, unboundlocalerror: local variable referenced before assignment, solution #1: passing parameters to the function, solution #2: use global keyword, solution #1: include else statement, solution #2: use global keyword.

Scope refers to a variable being only available inside the region where it was created. A variable created inside a function belongs to the local scope of that function, and we can only use that variable inside that function.

A variable created in the main body of the Python code is a global variable and belongs to the global scope. Global variables are available within any scope, global and local.

UnboundLocalError occurs when we try to modify a variable defined as local before creating it. If we only need to read a variable within a function, we can do so without using the global keyword. Consider the following example that demonstrates a variable var created with global scope and accessed from test_func :

If we try to assign a value to var within test_func , the Python interpreter will raise the UnboundLocalError:

This error occurs because when we make an assignment to a variable in a scope, that variable becomes local to that scope and overrides any variable with the same name in the global or outer scope.

var +=1 is similar to var = var + 1 , therefore the Python interpreter should first read var , perform the addition and assign the value back to var .

var is a variable local to test_func , so the variable is read or referenced before we have assigned it. As a result, the Python interpreter raises the UnboundLocalError.

Example #1: Accessing a Local Variable

Let’s look at an example where we define a global variable number. We will use the increment_func to increase the numerical value of number by 1.

Let’s run the code to see what happens:

The error occurs because we tried to read a local variable before assigning a value to it.

We can solve this error by passing a parameter to increment_func . This solution is the preferred approach. Typically Python developers avoid declaring global variables unless they are necessary. Let’s look at the revised code:

We have assigned a value to number and passed it to the increment_func , which will resolve the UnboundLocalError. Let’s run the code to see the result:

We successfully printed the value to the console.

We also can solve this error by using the global keyword. The global statement tells the Python interpreter that inside increment_func , the variable number is a global variable even if we assign to it in increment_func . Let’s look at the revised code:

Let’s run the code to see the result:

Example #2: Function with if-elif statements

Let’s look at an example where we collect a score from a player of a game to rank their level of expertise. The variable we will use is called score and the calculate_level function takes in score as a parameter and returns a string containing the player’s level .

In the above code, we have a series of if-elif statements for assigning a string to the level variable. Let’s run the code to see what happens:

The error occurs because we input a score equal to 40 . The conditional statements in the function do not account for a value below 55 , therefore when we call the calculate_level function, Python will attempt to return level without any value assigned to it.

We can solve this error by completing the set of conditions with an else statement. The else statement will provide an assignment to level for all scores lower than 55 . Let’s look at the revised code:

In the above code, all scores below 55 are given the beginner level. Let’s run the code to see what happens:

We can also create a global variable level and then use the global keyword inside calculate_level . Using the global keyword will ensure that the variable is available in the local scope of the calculate_level function. Let’s look at the revised code.

In the above code, we put the global statement inside the function and at the beginning. Note that the “default” value of level is beginner and we do not include the else statement in the function. Let’s run the code to see the result:

Congratulations on reading to the end of this tutorial! The UnboundLocalError: local variable referenced before assignment occurs when you try to reference a local variable before assigning a value to it. Preferably, you can solve this error by passing parameters to your function. Alternatively, you can use the global keyword.

If you have if-elif statements in your code where you assign a value to a local variable and do not account for all outcomes, you may encounter this error. In which case, you must include an else statement to account for the missing outcome.

For further reading on Python code blocks and structure, go to the article: How to Solve Python IndentationError: unindent does not match any outer indentation level .

Go to the  online courses page on Python  to learn more about Python for data science and machine learning.

Have fun and happy researching!

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Suf is a senior advisor in data science with deep expertise in Natural Language Processing, Complex Networks, and Anomaly Detection. Formerly a postdoctoral research fellow, he applied advanced physics techniques to tackle real-world, data-heavy industry challenges. Before that, he was a particle physicist at the ATLAS Experiment of the Large Hadron Collider. Now, he’s focused on bringing more fun and curiosity to the world of science and research online.

  • Suf https://researchdatapod.com/author/soofyserial/ Six Essential Tips After Two Years as a Research Scientist
  • Suf https://researchdatapod.com/author/soofyserial/ How to Sum the Elements of a Vector in C++
  • Suf https://researchdatapod.com/author/soofyserial/ How to Solve Python TypeError: can't multiply sequence by non-int of type 'float'
  • Suf https://researchdatapod.com/author/soofyserial/ How to Solve Python ModuleNotFoundError: No module named 'ConfigParser'

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How to Fix Local Variable Referenced Before Assignment Error in Python

How to Fix Local Variable Referenced Before Assignment Error in Python

Table of Contents

Fixing local variable referenced before assignment error.

In Python , when you try to reference a variable that hasn't yet been given a value (assigned), it will throw an error.

That error will look like this:

In this post, we'll see examples of what causes this and how to fix it.

Let's begin by looking at an example of this error:

If you run this code, you'll get

The issue is that in this line:

We are defining a local variable called value and then trying to use it before it has been assigned a value, instead of using the variable that we defined in the first line.

If we want to refer the variable that was defined in the first line, we can make use of the global keyword.

The global keyword is used to refer to a variable that is defined outside of a function.

Let's look at how using global can fix our issue here:

Global variables have global scope, so you can referenced them anywhere in your code, thus avoiding the error.

If you run this code, you'll get this output:

In this post, we learned at how to avoid the local variable referenced before assignment error in Python.

The error stems from trying to refer to a variable without an assigned value, so either make use of a global variable using the global keyword, or assign the variable a value before using it.

Thanks for reading!

unboundlocalerror local variable 'connection' referenced before assignment

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Python: UnboundLocalError: local variable referenced before assignment [closed]

I've got a piece of code here in Python Thread (Server) but when I run the client these error was found: "UnboundLocalError: local variable 'stop' referenced before assignment":

shx2's user avatar

  • 3 a duplicate of oh-so-many others ... –  shx2 Commented Mar 18, 2013 at 12:05
  • possible duplicate of UnboundLocalError: local variable ... referenced before assignment –  Kelly S. French Commented Mar 18, 2013 at 15:27

You only set the variable stop under very specific conditions and never set it to False . Add an explicit stop = False to the top of the run() function.

You probably want to set stop inside the while loop at some point, as it stands it'll never stop if stop = True is reached.

Martijn Pieters's user avatar

  • is stop = False is not enough as I declared it on the top? if I add stop = False to the top of the run() function the stop will never have a false value? –  Kit Commented Mar 18, 2013 at 12:08
  • @Kit: If msvcrt.kbhit() is True and msvcrt.getch() is equal to 's' , then stop is set to True ; your while 1 loop then will never see the local variable stop become False , because there is nothing inside of the loop that changes it's value. –  Martijn Pieters Commented Mar 18, 2013 at 12:10
  • @Wooble: thanks for that fix, I had to attend to something else for a few minutes and the formatting error slipped through. –  Martijn Pieters Commented Mar 18, 2013 at 12:14
  • I have another concern here Sir, Im expecting the code to just show 1 print because when I run the code, the message Client connection received! print many times, and also I want the value to be the same with the other open clients so other clients cant login also once I pressed 's' key –  Kit Commented Mar 18, 2013 at 12:21
  • @Kit: Your loop prints over and over again, because it is an infinite loop. You need to alter that loop to check for the stop event. How you do that with the other clients is up to you. I can help you with the UnboundLocal exception, and some general tips, but nothing more. –  Martijn Pieters Commented Mar 18, 2013 at 12:23

Not the answer you're looking for? Browse other questions tagged python or ask your own question .

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unboundlocalerror local variable 'connection' referenced before assignment

"UnboundLocalError: local variable 'os' referenced before assignment"

OS: macOS Sonoma 14.0 (on an M2 chip) PsychoPy version: 2023.2.3 Standard Standalone? (y/n) y What are you trying to achieve?: Upgrade an experiment from 2021.1.4 to 2023.2.3

Context: Our lab computers were updated and 2021.1.4 was no longer working (tasks would not start). I think it had something to do with losing support for python 2.X, but I decided to just move forward and upgrade versions. Note: I didn’t go straight to 2023.2.3, but tried some other versions along the way.

What did you try to make it work?: Installed v2023.2.3, updated “use version” to 2023.2.3 Other details: window backend = pyglet, audio library = ptb (but experiment has no sound anyway), keyboard backend = PsychToolbox

What specifically went wrong when you tried that?: I got an: "UnboundLocalError: local variable 'os' referenced before assignment" …referring to line 301 in the generated python script which uses os.chdir(_thisDir) early on in the “run” fuction. According to posts on this forum, an UnboundLocalError is usually due to a problematic conditions file. However, an error with the os package in the run function seems to be a deeper problem. Have I totally corrupted the experiment by changing versions?

(somewhat redacted) error output:

Seems like it could be something like this scoping issue , but I have no idea how the py code got this way.

What happens if use version is blank?

:frowning:

Update: if I set useVersion back to v2022.1.0 (one of the previous versions this experiment passed through), the error does not occur and I am able to run the experiment normally. However, this version is on the list of versions to avoid … so I’d rather avoid it if possible.

Hi, I came into the same problem today. And I’m completely new with Psychopy, so you may not find my solution useful given that you may have already tried it. But for other users as new as me, we should put code component before the other stimuli component (e.g., text, image). Psychopy needs to run the code before it runs the stimuli.

I think this will depend on whether you need the results of that code component to display other components in that routine. There are other situations where a code component would need to come at the end of a routine.

My friend was having the same issue as you. We have been able to solve it. The problem is exactly the scoping issue you were referring to.

The problem is this: In the version 2023.2.3, when you build the project, generated code already imports os in global scope. However, unlike some of the older versions (2021, 2022) all the code related to the routines are under a function run(). At the beginning of this run() function, os module is used with the function os.chdir(). Crucial part is that, this call is being made before any other routine. The problem arises when in one of your routines, you write the statement “import os”. When that happens, the scope issue arises because os is already defined globally, and you are defining it locally, but you already tried to access it before you define it locally. So the exact situation in stackoverflow post happens.

Why wasn’t it happening in older versions? Because in those versions, when you build the project, all the code related to your routines are still under the global scope, unlike newer versions where its under the local scope of run() function.

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unboundlocalerror local variable 'connection' referenced before assignment

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PGRouting Layer plugin "UnboundLocalError: local variable 'db' referenced before assignment"

I am trying to do some basic computations using the PGRouting plugin for QGIS, but I am getting this error all time:

I made a local installation of postgres 9.3.4, later I added postgis using the stack builder, and finally I followed the instructions posted here: PGRouting 2.0 for windows . I also installed python-psycopg2 for my version of python.

The SQL query runs well in pgAdminIII, but I can not make that QGIS plugin work.

  • unboundlocalerror

PolyGeo's user avatar

  • 1 I have seen this kind of error at the different post. Could you check the user name and password are saved at creating connection time ? gis.stackexchange.com/questions/87111/… –  sanak Commented Apr 8, 2014 at 5:00
  • Dear sanak, your answer has solved my problem. Thank you so much. –  gtapko Commented Apr 8, 2014 at 5:24

In order to make the plugin work, I needed to save both my username and password on the database connection.

til's user avatar

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unboundlocalerror local variable 'connection' referenced before assignment

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UnboundLocalError: local variable 'wmi' referenced before assignment

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Silly Frenchman

Feb-10-2022, 12:37 PM

How can i solve it?



Verb Conjugator

Feb-10-2022, 03:25 PM ilknurg Wrote: import wmi_client_wrapper as wmi
...
wmi = wmi.WmiClientWrapper(...)You should not introduce a variable with the same name as the (alias of) the module you imported. likes this post

Feb-10-2022, 07:36 PM (This post was last modified: Feb-10-2022, 07:37 PM by .) likes this post
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2.9.10: UnboundLocalError: local variable 'module_style' referenced before assignment #70168

@resmo

resmo commented Jun 19, 2020 • edited Loading

after upgrade from 2.9.9 to 2.9.10 we see an exception in a task using

: my.example.com gather_facts: yes tasks: - name: make something delegate_facts: True delegate_to: other.example.com lineinfile: path: /tmp/foo.txt regexp: '^Listen ' insertafter: '^#Listen ' line: Listen 8080

@mkrizek

mkrizek commented Jun 19, 2020

I couldn't reproduce this with an arbitrary lineinfile task. We'll need you to provide a minimal reproducer.

Sorry, something went wrong.

@ansibot

I added a reproducer. It seems related to

  • 👍 2 reactions

Sounds like this might be related to .

cc

@srgvg

srgvg commented Jun 19, 2020

Can confirm, we have the same problem, though it only triggers in particular case (localhost -> localhost)

Playbook:

Results:

Since we now pass instead of to , we need to update information in for the next iteration too. The following makes the problem go away:

index 83c7715d3e..62a185a3fd 100644 --- a/lib/ansible/plugins/action/__init__.py +++ b/lib/ansible/plugins/action/__init__.py @@ -249,7 +249,9 @@ class ActionBase(with_metaclass(ABCMeta, object)): # store in local task_vars facts collection for the retry and any other usages in this worker if use_vars.get('ansible_facts') is None: task_vars['ansible_facts'] = {} + use_vars['ansible_facts'] = {} task_vars['ansible_facts'][discovered_key] = self._discovered_interpreter + use_vars['ansible_facts'][discovered_key] = self._discovered_interpreter # preserve this so _execute_module can propagate back to controller as a fact self._discovered_interpreter_key = discovered_key else:

The similar would need to be changed in the branch as well. I am not sure if changing is needed though, or if changing all occurrences of to would be the fix.

@mkrizek

samdoran commented Jun 24, 2020

Reopening since the fix for this was reverted in .

@samdoran

gfidente commented Jun 25, 2020 • edited Loading

as per IRC chat in #ansible-devel :

iirc the issue was related to using AND AND not being explicitly set (set set to )

that explains why it's seen in ceph-ansible ci but we aren't seeing it in tripleo ci; in tripleo we forcibly set ansible_python_interpreter [1]

@fultonj

Successfully merging a pull request may close this issue.

@resmo

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    I made a local installation of postgres 9.3.4, later I added postgis using the stack builder, and finally I followed the instructions posted here: PGRouting 2.0 for windows. I also installed python-psycopg2 for my version of python.

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